Res371 Study Guide

------------------------------------------------- RES/341 Week 4 Answer Guide - Statistics 5.62 -A certain(p) sheet has two freelancer alternators to provide electrical power. The luck that a devoted alternator ordain breach on a 1-hour flight is .02. What is the forecast that (a) both will break up? (b) neither will bomb? (c) One or the otherwise will cave in? essay all steps carefully. (a) Both Fail N = 2, p = .02, a = alternator 1, b = alternator 2 Pa Ç Pb = (.02)(.02) = 0.0004 The fortune that both will fail is 0.0004 or 0.04% b) Neither entrust Fail 1-( Pa + Pb) + (Pa Ç Pb) = (1 - 0.04) + 0.0004 = 0.9604 The probability that neither will fail is 0.9604 or 96.04% (c) One or the other will fail Pa + Pb - (Pa Ç Pb)= 0.02 + 0.02 0.0004 = 0.0396 The probability that one or the other will fail is 0.0396 or 3.96% 5.70 - * The probability is 1 in 4,000,000 that a virtuoso auto tripper in the fall in States will matter in a dimity. Over a life time, an average U.S. number one wood takes 50,000 trips. (a) What is the probability of a calamitous misfortune everyplace a lifetime? excuse your reasoning carefully. Hint: Assume independent events. why faculty the supposal of independence be violate? (b) Why susceptibility a driver be tempted non to use a layabout belt just on this trip?

(a) What is the probability of a fatal accident over a lifetime? N = 2, p = 0.00000025, a = fatal accident, b = no fatal accident Pa = 1 Pb  Pa = 1 0.00000025 Pa = 0.99999975 ^ 50000 = 0.987577799 Pa = 1 0.987577799 Pa = 0.012422201 The probability of a fatal accident over a lifetime is 0.01242220! 1 or 1.24%. I came to this conclusion by counterbalance using the attendant rule. There are two manageable outcomes from each trip which are fatal accident (a), and non-fatal accident (b). From here, I embossed the result to the 50,000th power for each thinkable trip. This result was subtracted from 1 to get the final probability of 1.24%. Why might the assumption of independence be violated? The assumption...If you deprivation to get a full essay, order it on our website: OrderCustomPaper.com

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